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- Question: Why Derrived pointer binds statically to derived object?
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Why Derrived pointer binds statically to derived object?
When a pointer of a derived class type is derived from a base class pointer, it binds statically to the derived object because the type of the pointer is determined at compile-time based on its declared type, regardless of the actual object it points to at runtime.
For example, suppose we have a base class Animal
and a derived class Dog
that inherits from Animal
. If we create a Dog
object and assign its address to a pointer of type Animal*
, the pointer will statically bind to the Animal
portion of the Dog
object. This means that the pointer can only access the members and functions that are part of the Animal
base class, even if the actual object it points to is a Dog
object with additional members and functions.
To access the members and functions specific to the Dog
class, we need to either cast the pointer to a Dog*
or use virtual functions that are overridden in the Dog
class. Virtual functions allow us to dynamically bind to the correct function based on the actual object type at runtime, whereas static binding occurs at compile-time based on the declared type of the pointer.
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164 Base Class Pointer Derived Class Object
Why can’t a derived pointer reference a base object?
A derived pointer is a pointer that points to an object of a derived class, while a base object is an object of a base class. In C++, a derived class inherits from its base class, which means that it contains all the data members and member functions of the base class.
When a derived pointer references a base object, it may lead to unexpected behavior or even errors. This is because a base object may not have all the data members or member functions of the derived class. When a derived pointer tries to access a data member or member function of the derived class that is not present in the base object, it may result in undefined behavior, which can lead to crashes, segmentation faults, or other errors.
To avoid such errors, it is recommended to use a base pointer to reference a base object, and a derived pointer to reference a derived object. This ensures that the pointer is pointing to an object that has all the data members and member functions that it needs to access, and that the behavior of the program is well-defined.
What happens when a base class pointer points to a derived class object?
When a base class pointer points to a derived class object, it is called “upcasting”. In this scenario, the base class pointer can only access the members of the base class that are inherited by the derived class.
If the derived class has overridden any of the base class functions, then the derived class’s function will be called instead of the base class function. This is because function calls are resolved at runtime based on the actual type of the object pointed to by the pointer, rather than the type of the pointer itself.
However, if the derived class has defined any additional members or functions that are not part of the base class, those members and functions will not be accessible through the base class pointer. To access those members or functions, you would need to downcast the pointer back to the derived class type.
In summary, when a base class pointer points to a derived class object, you can only access the members of the base class that are inherited by the derived class, and any overridden base class functions will be called based on the actual type of the object pointed to by the pointer.
Why use base pointer for derived class object?
In C++, when a derived class is created, it inherits all the members of its base class(es). This includes not only the member variables and member functions, but also any non-virtual member functions that the base class has defined.
When a derived class object is created, it contains both its own member variables and the member variables inherited from its base class(es). To access the base class members from within the derived class, you can use a pointer to the base class.
One common way to use such a pointer is to define a base class pointer that points to a derived class object. This is useful when you want to pass a derived class object to a function that takes a pointer to its base class as an argument.
For example, suppose you have a base class called Animal
and a derived class called Cat
. You could define a function that takes a pointer to an Animal
object, like this:
cvoid printAnimalName(Animal* animal) { std::cout << "The animal's name is " << animal->getName() << std::endl; }
Then, if you have a Cat
object, you could pass it to the function using a base class pointer:
scssCat myCat("Fluffy"); printAnimalName(&myCat);
In this example, myCat
is a Cat
object, but we pass it to printAnimalName()
using a pointer to its base class Animal
. The function is still able to access the getName()
function of the Cat
object because it is defined in the Animal
base class and inherited by the Cat
class.
Using a base class pointer to access a derived class object is a common technique in object-oriented programming, as it allows you to write more flexible and reusable code.
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